Base | Representation |
---|---|
bin | 11101100100100001101101… |
… | …001000010100101010010100 |
3 | 122001110222122212222010101122 |
4 | 131210201231020110222110 |
5 | 114021243421244334304 |
6 | 1140333420435543112 |
7 | 36252023332405022 |
oct | 3544415510245224 |
9 | 561428585863348 |
10 | 130053440621204 |
11 | 38491399820981 |
12 | 1270528a15aa98 |
13 | 5774caa0a1239 |
14 | 2418897831712 |
15 | 1007ec601b9be |
hex | 76486d214a94 |
130053440621204 has 12 divisors (see below), whose sum is σ = 228166804518324. Its totient is φ = 64862925044544.
The previous prime is 130053440621179. The next prime is 130053440621213. The reversal of 130053440621204 is 402126044350031.
It can be written as a sum of positive squares in 2 ways, for example, as 117640488288400 + 12412952332804 = 10846220^2 + 3523202^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40948814729 + ... + 40948817904.
It is an arithmetic number, because the mean of its divisors is an integer number (19013900376527).
Almost surely, 2130053440621204 is an apocalyptic number.
It is an amenable number.
130053440621204 is a deficient number, since it is larger than the sum of its proper divisors (98113363897120).
130053440621204 is a wasteful number, since it uses less digits than its factorization.
130053440621204 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81897633034 (or 81897633032 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 130053440621204 its reverse (402126044350031), we get a palindrome (532179484971235).
The spelling of 130053440621204 in words is "one hundred thirty trillion, fifty-three billion, four hundred forty million, six hundred twenty-one thousand, two hundred four".
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