Search a number
-
+
13005476941 = 62299208759
BaseRepresentation
bin11000001110010111…
…11101010001001101
31020120101002200102011
430013023331101031
5203113400230231
65550304301221
7640200505252
oct140713752115
936511080364
1013005476941
115574286356
12262b611811
1312c356b8b2
148b5393429
15511b849b1
hex3072fd44d

13005476941 has 4 divisors (see below), whose sum is σ = 13005748000. Its totient is φ = 13005205884.

The previous prime is 13005476863. The next prime is 13005476959. The reversal of 13005476941 is 14967450031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13005476941 - 211 = 13005474893 is a prime.

It is a super-3 number, since 3×130054769413 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13005476894 and 13005476903.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13005476641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42081 + ... + 166678.

It is an arithmetic number, because the mean of its divisors is an integer number (3251437000).

Almost surely, 213005476941 is an apocalyptic number.

It is an amenable number.

13005476941 is a deficient number, since it is larger than the sum of its proper divisors (271059).

13005476941 is an equidigital number, since it uses as much as digits as its factorization.

13005476941 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 271058.

The product of its (nonzero) digits is 90720, while the sum is 40.

The spelling of 13005476941 in words is "thirteen billion, five million, four hundred seventy-six thousand, nine hundred forty-one".

Divisors: 1 62299 208759 13005476941