13005474893 has 2 divisors, whose sum is σ = 13005474894. Its totient is φ = 13005474892.

The previous prime is 13005474887. The next prime is 13005474899. The reversal of 13005474893 is 39847450031.

It is a balanced prime because it is at equal distance from previous prime (13005474887) and next prime (13005474899).

It can be written as a sum of positive squares in only one way, i.e., 9741295204 + 3264179689 = 98698^2 + 57133^2 .

It is a cyclic number.

It is not a de Polignac number, because 13005474893 - 2¹⁴ = 13005458509 is a prime.

It is a super-2 number, since 2×13005474893² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13005474899) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502737446 + 6502737447.

It is an arithmetic number, because the mean of its divisors is an integer number (6502737447).

Almost surely, 2^13005474893 is an apocalyptic number.

It is an amenable number.

13005474893 is a deficient number, since it is larger than the sum of its proper divisors (1).

13005474893 is an equidigital number, since it uses as much as digits as its factorization.

13005474893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 44.

The spelling of 13005474893 in words is "thirteen billion, five million, four hundred seventy-four thousand, eight hundred ninety-three".