Base | Representation |
---|---|
bin | 11101100100100011011001… |
… | …001010011000011100100001 |
3 | 122001111011100012110121022211 |
4 | 131210203121022120130201 |
5 | 114021311124243202241 |
6 | 1140334320343402121 |
7 | 36252116261255503 |
oct | 3544433112303441 |
9 | 561434305417284 |
10 | 130055253100321 |
11 | 384921399292aa |
12 | 127056b5153341 |
13 | 57752087403a3 |
14 | 24189ca435d73 |
15 | 10080801dc781 |
hex | 7648d9298721 |
130055253100321 has 2 divisors, whose sum is σ = 130055253100322. Its totient is φ = 130055253100320.
The previous prime is 130055253100243. The next prime is 130055253100327. The reversal of 130055253100321 is 123001352550031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88916318907025 + 41138934193296 = 9429545^2 + 6413964^2 .
It is a cyclic number.
It is not a de Polignac number, because 130055253100321 - 231 = 130053105616673 is a prime.
It is not a weakly prime, because it can be changed into another prime (130055253100327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65027626550160 + 65027626550161.
It is an arithmetic number, because the mean of its divisors is an integer number (65027626550161).
Almost surely, 2130055253100321 is an apocalyptic number.
It is an amenable number.
130055253100321 is a deficient number, since it is larger than the sum of its proper divisors (1).
130055253100321 is an equidigital number, since it uses as much as digits as its factorization.
130055253100321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 130055253100321 in words is "one hundred thirty trillion, fifty-five billion, two hundred fifty-three million, one hundred thousand, three hundred twenty-one".
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