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13005550344142 = 26502775172071
BaseRepresentation
bin1011110101000001011100…
…1101010101011111001110
31201001022121011110020002001
42331100113031111133032
53201040331342003032
643354400051422514
72511422442632626
oct275202715253716
951038534406061
1013005550344142
11416469412a474
1215606905b4a3a
13734558848015
1432d687225886
15178486a9d3e7
hexbd4173557ce

13005550344142 has 4 divisors (see below), whose sum is σ = 19508325516216. Its totient is φ = 6502775172070.

The previous prime is 13005550344131. The next prime is 13005550344173. The reversal of 13005550344142 is 24144305550031.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×130055503441423 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3251387586034 + ... + 3251387586037.

It is an arithmetic number, because the mean of its divisors is an integer number (4877081379054).

Almost surely, 213005550344142 is an apocalyptic number.

13005550344142 is a deficient number, since it is larger than the sum of its proper divisors (6502775172074).

13005550344142 is an equidigital number, since it uses as much as digits as its factorization.

13005550344142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6502775172073.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 13005550344142 its reverse (24144305550031), we get a palindrome (37149855894173).

The spelling of 13005550344142 in words is "thirteen trillion, five billion, five hundred fifty million, three hundred forty-four thousand, one hundred forty-two".

Divisors: 1 2 6502775172071 13005550344142