Base | Representation |
---|---|
bin | 11101100100101010101110… |
… | …011100101110100111101110 |
3 | 122001111220122220111220001020 |
4 | 131210222232130232213232 |
5 | 114021423240331032141 |
6 | 1140342101520155010 |
7 | 36252515343360204 |
oct | 3544525634564756 |
9 | 561456586456036 |
10 | 130063126424046 |
11 | 3849550a144a12 |
12 | 12707131a68a66 |
13 | 5775b9195c81a |
14 | 2419135d67074 |
15 | 1008391514266 |
hex | 764aae72e9ee |
130063126424046 has 16 divisors (see below), whose sum is σ = 260126470344144. Its totient is φ = 43354339225344.
The previous prime is 130063126424029. The next prime is 130063126424123. The reversal of 130063126424046 is 640424621360031.
It is a junction number, because it is equal to n+sod(n) for n = 130063126423989 and 130063126424007.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 693865 + ... + 16143348.
It is an arithmetic number, because the mean of its divisors is an integer number (16257904396509).
Almost surely, 2130063126424046 is an apocalyptic number.
130063126424046 is an abundant number, since it is smaller than the sum of its proper divisors (130063343920098).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130063126424046 is a wasteful number, since it uses less digits than its factorization.
130063126424046 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18124675.
The product of its (nonzero) digits is 497664, while the sum is 42.
Adding to 130063126424046 its reverse (640424621360031), we get a palindrome (770487747784077).
The spelling of 130063126424046 in words is "one hundred thirty trillion, sixty-three billion, one hundred twenty-six million, four hundred twenty-four thousand, forty-six".
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