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130077456097 is a prime number
BaseRepresentation
bin111100100100100111…
…0000111011011100001
3110102202022200102102011
41321021032013123201
54112344312043342
6135431243152521
712253304063611
oct1711116073341
9412668612364
10130077456097
1150190373036
1221262815741
13c35cc54044
14641d8aca41
1535b4a63717
hex1e493876e1

130077456097 has 2 divisors, whose sum is σ = 130077456098. Its totient is φ = 130077456096.

The previous prime is 130077456073. The next prime is 130077456181. The reversal of 130077456097 is 790654770031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98196996496 + 31880459601 = 313364^2 + 178551^2 .

It is a cyclic number.

It is not a de Polignac number, because 130077456097 - 235 = 95717717729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130077456097.

It is not a weakly prime, because it can be changed into another prime (130077456497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65038728048 + 65038728049.

It is an arithmetic number, because the mean of its divisors is an integer number (65038728049).

Almost surely, 2130077456097 is an apocalyptic number.

It is an amenable number.

130077456097 is a deficient number, since it is larger than the sum of its proper divisors (1).

130077456097 is an equidigital number, since it uses as much as digits as its factorization.

130077456097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1111320, while the sum is 49.

The spelling of 130077456097 in words is "one hundred thirty billion, seventy-seven million, four hundred fifty-six thousand, ninety-seven".