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13008358273 is a prime number
BaseRepresentation
bin11000001110101101…
…11100101110000001
31020120120112001212011
430013112330232001
5203120114431043
65550450132521
7640234135531
oct140726745601
936516461764
1013008358273
115575974119
122630581141
1312c403a221
148b59034c1
1551205359d
hex3075bcb81

13008358273 has 2 divisors, whose sum is σ = 13008358274. Its totient is φ = 13008358272.

The previous prime is 13008358249. The next prime is 13008358283. The reversal of 13008358273 is 37285380031.

13008358273 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7426475329 + 5581882944 = 86177^2 + 74712^2 .

It is an emirp because it is prime and its reverse (37285380031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13008358273 - 25 = 13008358241 is a prime.

It is not a weakly prime, because it can be changed into another prime (13008358243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6504179136 + 6504179137.

It is an arithmetic number, because the mean of its divisors is an integer number (6504179137).

Almost surely, 213008358273 is an apocalyptic number.

It is an amenable number.

13008358273 is a deficient number, since it is larger than the sum of its proper divisors (1).

13008358273 is an equidigital number, since it uses as much as digits as its factorization.

13008358273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

It can be divided in two parts, 130083 and 58273, that added together give a square (188356 = 4342).

The spelling of 13008358273 in words is "thirteen billion, eight million, three hundred fifty-eight thousand, two hundred seventy-three".