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130094178000 = 24353194326539
BaseRepresentation
bin111100100101000110…
…1111001111011010000
3110102210111010222112220
41321022031321323100
54112413102144000
6135433041421040
712253566160533
oct1711215717320
9412714128486
10130094178000
1150199854496
122126833a780
13c36355a367
146421bc2a1a
1535b62681a0
hex1e4a379ed0

130094178000 has 320 divisors, whose sum is σ = 451782988800. Its totient is φ = 32100364800.

The previous prime is 130094177987. The next prime is 130094178029. The reversal of 130094178000 is 871490031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4888731 + ... + 4915269.

It is an arithmetic number, because the mean of its divisors is an integer number (1411821840).

Almost surely, 2130094178000 is an apocalyptic number.

130094178000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130094178000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (225891494400).

130094178000 is an abundant number, since it is smaller than the sum of its proper divisors (321688810800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130094178000 is a wasteful number, since it uses less digits than its factorization.

130094178000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26627 (or 26611 counting only the distinct ones).

The product of its (nonzero) digits is 6048, while the sum is 33.

The spelling of 130094178000 in words is "one hundred thirty billion, ninety-four million, one hundred seventy-eight thousand".