Base | Representation |
---|---|
bin | 10010111011101001101… |
… | …001111011001001111001 |
3 | 11121101002221102010102212 |
4 | 102323221221323021321 |
5 | 132303422023024141 |
6 | 2433400553304505 |
7 | 162664666164614 |
oct | 22735151731171 |
9 | 4541087363385 |
10 | 1301000204921 |
11 | 461829775a2a |
12 | 190186405135 |
13 | 958b73a6981 |
14 | 46d7c34b17b |
15 | 23c96b472eb |
hex | 12ee9a7b279 |
1301000204921 has 2 divisors, whose sum is σ = 1301000204922. Its totient is φ = 1301000204920.
The previous prime is 1301000204909. The next prime is 1301000204939. The reversal of 1301000204921 is 1294020001031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 800675988025 + 500324216896 = 894805^2 + 707336^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301000204921 - 218 = 1300999942777 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301000204521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650500102460 + 650500102461.
It is an arithmetic number, because the mean of its divisors is an integer number (650500102461).
Almost surely, 21301000204921 is an apocalyptic number.
It is an amenable number.
1301000204921 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301000204921 is an equidigital number, since it uses as much as digits as its factorization.
1301000204921 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1301000204921 its reverse (1294020001031), we get a palindrome (2595020205952).
The spelling of 1301000204921 in words is "one trillion, three hundred one billion, two hundred four thousand, nine hundred twenty-one".
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