Base | Representation |
---|---|
bin | 10010111011101001101… |
… | …101000100101010111011 |
3 | 11121101002222222001200121 |
4 | 102323221231010222323 |
5 | 132303422230432311 |
6 | 2433401023114111 |
7 | 162665006203222 |
oct | 22735155045273 |
9 | 4541088861617 |
10 | 1301001030331 |
11 | 46182a18a092 |
12 | 190186742937 |
13 | 958b7605592 |
14 | 46d7c4c3cb9 |
15 | 23c96c5bb71 |
hex | 12ee9b44abb |
1301001030331 has 2 divisors, whose sum is σ = 1301001030332. Its totient is φ = 1301001030330.
The previous prime is 1301001030299. The next prime is 1301001030383. The reversal of 1301001030331 is 1330301001031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1301001030331 - 25 = 1301001030299 is a prime.
It is a super-2 number, since 2×13010010303312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1301001030031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650500515165 + 650500515166.
It is an arithmetic number, because the mean of its divisors is an integer number (650500515166).
Almost surely, 21301001030331 is an apocalyptic number.
1301001030331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301001030331 is an equidigital number, since it uses as much as digits as its factorization.
1301001030331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 1301001030331 its reverse (1330301001031), we get a palindrome (2631302031362).
The spelling of 1301001030331 in words is "one trillion, three hundred one billion, one million, thirty thousand, three hundred thirty-one".
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