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130100120023513 is a prime number
BaseRepresentation
bin11101100101001101001011…
…011100000111000111011001
3122001122110011001111110022211
4131211031023130013013121
5114023030021211223023
61140411100421315121
736255265153646653
oct3545151334070731
9561573131443284
10130100120023513
11384aa173060812
1212712336b65aa1
135779508bc9453
14241ac451436d3
1510093090e0a0d
hex76534b7071d9

130100120023513 has 2 divisors, whose sum is σ = 130100120023514. Its totient is φ = 130100120023512.

The previous prime is 130100120023493. The next prime is 130100120023537. The reversal of 130100120023513 is 315320021001031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130098045038809 + 2074984704 = 11406053^2 + 45552^2 .

It is a cyclic number.

It is not a de Polignac number, because 130100120023513 - 213 = 130100120015321 is a prime.

It is a super-2 number, since 2×1301001200235132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130100120023553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65050060011756 + 65050060011757.

It is an arithmetic number, because the mean of its divisors is an integer number (65050060011757).

Almost surely, 2130100120023513 is an apocalyptic number.

It is an amenable number.

130100120023513 is a deficient number, since it is larger than the sum of its proper divisors (1).

130100120023513 is an equidigital number, since it uses as much as digits as its factorization.

130100120023513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 130100120023513 its reverse (315320021001031), we get a palindrome (445420141024544).

The spelling of 130100120023513 in words is "one hundred thirty trillion, one hundred billion, one hundred twenty million, twenty-three thousand, five hundred thirteen".