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13010012231323 is a prime number
BaseRepresentation
bin1011110101010010000100…
…1010000101011010011011
31201001202010010021120121211
42331110201022011122123
53201124001112400243
643400414521243551
72511641142225232
oct275244112053233
951052103246554
1013010012231323
114166573809338
1215615169335b7
13734aba068c53
1432d98ba4db19
1517864865dd9d
hexbd52128569b

13010012231323 has 2 divisors, whose sum is σ = 13010012231324. Its totient is φ = 13010012231322.

The previous prime is 13010012231309. The next prime is 13010012231423. The reversal of 13010012231323 is 32313221001031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13010012231323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13010012231294 and 13010012231303.

It is not a weakly prime, because it can be changed into another prime (13010012231423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505006115661 + 6505006115662.

It is an arithmetic number, because the mean of its divisors is an integer number (6505006115662).

Almost surely, 213010012231323 is an apocalyptic number.

13010012231323 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010012231323 is an equidigital number, since it uses as much as digits as its factorization.

13010012231323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13010012231323 its reverse (32313221001031), we get a palindrome (45323233232354).

The spelling of 13010012231323 in words is "thirteen trillion, ten billion, twelve million, two hundred thirty-one thousand, three hundred twenty-three".