Base | Representation |
---|---|
bin | 10010111011101010010… |
… | …111000010011101111001 |
3 | 11121101010202122222020212 |
4 | 102323222113002131321 |
5 | 132303433040000403 |
6 | 2433402055000505 |
7 | 162665201542166 |
oct | 22735227023571 |
9 | 4541122588225 |
10 | 1301012031353 |
11 | 461835413341 |
12 | 19018a369135 |
13 | 958b9987968 |
14 | 46d7db4906d |
15 | 23c97bd14d8 |
hex | 12eea5c2779 |
1301012031353 has 2 divisors, whose sum is σ = 1301012031354. Its totient is φ = 1301012031352.
The previous prime is 1301012031311. The next prime is 1301012031383. The reversal of 1301012031353 is 3531302101031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1213275814144 + 87736217209 = 1101488^2 + 296203^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301012031353 - 26 = 1301012031289 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301012031383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650506015676 + 650506015677.
It is an arithmetic number, because the mean of its divisors is an integer number (650506015677).
Almost surely, 21301012031353 is an apocalyptic number.
It is an amenable number.
1301012031353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301012031353 is an equidigital number, since it uses as much as digits as its factorization.
1301012031353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 1301012031353 its reverse (3531302101031), we get a palindrome (4832314132384).
The spelling of 1301012031353 in words is "one trillion, three hundred one billion, twelve million, thirty-one thousand, three hundred fifty-three".
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