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130101401 is a prime number
BaseRepresentation
bin1111100000100…
…11000010011001
3100001210211120102
413300103002121
5231301221101
620524305145
73136562243
oct760230231
9301724512
10130101401
1167491121
12376a21b5
1320c529a1
14133c9093
15b64d86b
hex7c13099

130101401 has 2 divisors, whose sum is σ = 130101402. Its totient is φ = 130101400.

The previous prime is 130101371. The next prime is 130101427. The reversal of 130101401 is 104101031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83247376 + 46854025 = 9124^2 + 6845^2 .

It is an emirp because it is prime and its reverse (104101031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130101401 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130103401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65050700 + 65050701.

It is an arithmetic number, because the mean of its divisors is an integer number (65050701).

Almost surely, 2130101401 is an apocalyptic number.

It is an amenable number.

130101401 is a deficient number, since it is larger than the sum of its proper divisors (1).

130101401 is an equidigital number, since it uses as much as digits as its factorization.

130101401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 130101401 is about 11406.2001122197. The cubic root of 130101401 is about 506.7113797009.

Adding to 130101401 its reverse (104101031), we get a palindrome (234202432).

The spelling of 130101401 in words is "one hundred thirty million, one hundred one thousand, four hundred one".