Base | Representation |
---|---|
bin | 11101100101001111000010… |
… | …101001011010101101000000 |
3 | 122001122122022102210210201220 |
4 | 131211033002221122231000 |
5 | 114023043120210002240 |
6 | 1140412031103555040 |
7 | 36255365550324066 |
oct | 3545170251325500 |
9 | 561578272723656 |
10 | 130102120000320 |
11 | 384aaaa9a91a06 |
12 | 127127b48bba80 |
13 | 5779767366090 |
14 | 241ad949d4036 |
15 | 10093c499b5d0 |
hex | 7653c2a5ab40 |
130102120000320 has 448 divisors, whose sum is σ = 447171781539840. Its totient is φ = 31858077081600.
The previous prime is 130102120000291. The next prime is 130102120000337. The reversal of 130102120000320 is 23000021201031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 130102120000320.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6085499391 + ... + 6085520769.
It is an arithmetic number, because the mean of its divisors is an integer number (998151298080).
Almost surely, 2130102120000320 is an apocalyptic number.
130102120000320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130102120000320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (223585890769920).
130102120000320 is an abundant number, since it is smaller than the sum of its proper divisors (317069661539520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130102120000320 is a wasteful number, since it uses less digits than its factorization.
130102120000320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23934 (or 23924 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 130102120000320 its reverse (23000021201031), we get a palindrome (153102141201351).
The spelling of 130102120000320 in words is "one hundred thirty trillion, one hundred two billion, one hundred twenty million, three hundred twenty", and thus it is an aban number.
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