Base | Representation |
---|---|
bin | 11101100101001111001111… |
… | …010010100100000011100011 |
3 | 122001122122212012221020210122 |
4 | 131211033033102210003203 |
5 | 114023044034010104443 |
6 | 1140412104122150455 |
7 | 36255404034260546 |
oct | 3545171722440343 |
9 | 561578765836718 |
10 | 130102332113123 |
11 | 385000a8798447 |
12 | 1271285395242b |
13 | 577979c2a1806 |
14 | 241adb4c4a85d |
15 | 10093d83e9968 |
hex | 7653cf4a40e3 |
130102332113123 has 2 divisors, whose sum is σ = 130102332113124. Its totient is φ = 130102332113122.
The previous prime is 130102332113111. The next prime is 130102332113141. The reversal of 130102332113123 is 321311233201031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130102332113123 - 214 = 130102332096739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130102332113092 and 130102332113101.
It is not a weakly prime, because it can be changed into another prime (130102332113153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051166056561 + 65051166056562.
It is an arithmetic number, because the mean of its divisors is an integer number (65051166056562).
Almost surely, 2130102332113123 is an apocalyptic number.
130102332113123 is a deficient number, since it is larger than the sum of its proper divisors (1).
130102332113123 is an equidigital number, since it uses as much as digits as its factorization.
130102332113123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 130102332113123 its reverse (321311233201031), we get a palindrome (451413565314154).
The spelling of 130102332113123 in words is "one hundred thirty trillion, one hundred two billion, three hundred thirty-two million, one hundred thirteen thousand, one hundred twenty-three".
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