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13010234130433 is a prime number
BaseRepresentation
bin1011110101010010111001…
…1000100100000000000001
31201001202200120211012222101
42331110232120210000001
53201124424414133213
643400452525310401
72511646505311351
oct275245630440001
951052616735871
1013010234130433
114166677a99431
121561579105401
13734b2401cbb7
1432d9ad2d2b61
1517865cd91bdd
hexbd52e624001

13010234130433 has 2 divisors, whose sum is σ = 13010234130434. Its totient is φ = 13010234130432.

The previous prime is 13010234130403. The next prime is 13010234130449. The reversal of 13010234130433 is 33403143201031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7752788690689 + 5257445439744 = 2784383^2 + 2292912^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13010234130433 is a prime.

It is not a weakly prime, because it can be changed into another prime (13010234130403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505117065216 + 6505117065217.

It is an arithmetic number, because the mean of its divisors is an integer number (6505117065217).

Almost surely, 213010234130433 is an apocalyptic number.

It is an amenable number.

13010234130433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010234130433 is an equidigital number, since it uses as much as digits as its factorization.

13010234130433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 13010234130433 its reverse (33403143201031), we get a palindrome (46413377331464).

The spelling of 13010234130433 in words is "thirteen trillion, ten billion, two hundred thirty-four million, one hundred thirty thousand, four hundred thirty-three".