1301033312431 has 4 divisors (see below), whose sum is σ = 1301051435112. Its totient is φ = 1301015189752.

The previous prime is 1301033312419. The next prime is 1301033312441. The reversal of 1301033312431 is 1342133301031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301033312431 - 2²¹ = 1301031215279 is a prime.

It is a super-2 number, since 2×1301033312431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301033312396 and 1301033312405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301033312441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8953225 + ... + 9097378.

It is an arithmetic number, because the mean of its divisors is an integer number (325262858778).

Almost surely, 2^{1301033312431} is an apocalyptic number.

1301033312431 is a deficient number, since it is larger than the sum of its proper divisors (18122681).

1301033312431 is an equidigital number, since it uses as much as digits as its factorization.

1301033312431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18122680.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1301033312431 its reverse (1342133301031), we get a palindrome (2643166613462).

The spelling of 1301033312431 in words is "one trillion, three hundred one billion, thirty-three million, three hundred twelve thousand, four hundred thirty-one".