Base | Representation |
---|---|
bin | 11101100101010000110100… |
… | …010100111100111010001011 |
3 | 122001122211020100121112000111 |
4 | 131211100310110330322023 |
5 | 114023111021433104102 |
6 | 1140412544234415151 |
7 | 36255464036506633 |
oct | 3545206424747213 |
9 | 561584210545014 |
10 | 130104027238027 |
11 | 38500898630917 |
12 | 127130475914b7 |
13 | 57799ac5320bb |
14 | 241b0d60236c3 |
15 | 1009487138cd7 |
hex | 76543453ce8b |
130104027238027 has 2 divisors, whose sum is σ = 130104027238028. Its totient is φ = 130104027238026.
The previous prime is 130104027238013. The next prime is 130104027238033. The reversal of 130104027238027 is 720832720401031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130104027238027 - 215 = 130104027205259 is a prime.
It is a super-2 number, since 2×1301040272380272 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130104027238037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65052013619013 + 65052013619014.
It is an arithmetic number, because the mean of its divisors is an integer number (65052013619014).
Almost surely, 2130104027238027 is an apocalyptic number.
130104027238027 is a deficient number, since it is larger than the sum of its proper divisors (1).
130104027238027 is an equidigital number, since it uses as much as digits as its factorization.
130104027238027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112896, while the sum is 40.
Adding to 130104027238027 its reverse (720832720401031), we get a palindrome (850936747639058).
The spelling of 130104027238027 in words is "one hundred thirty trillion, one hundred four billion, twenty-seven million, two hundred thirty-eight thousand, twenty-seven".
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