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1301042480734 = 2681229954923
BaseRepresentation
bin10010111011101100001…
…011001100011001011110
311121101012212221221221201
4102323230023030121132
5132304013333340414
62433405103350114
7162666021421663
oct22735413143136
94541185857851
101301042480734
11461850620417
121901985b233a
13958c3089349
1446d83bd3a6a
1523c9a6e8574
hex12eec2cc65e

1301042480734 has 8 divisors (see below), whose sum is σ = 1951568629560. Its totient is φ = 650519604216.

The previous prime is 1301042480681. The next prime is 1301042480743. The reversal of 1301042480734 is 4370842401031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13010424807342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1301042480693 and 1301042480702.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 884997 + ... + 1839919.

It is an arithmetic number, because the mean of its divisors is an integer number (243946078695).

Almost surely, 21301042480734 is an apocalyptic number.

1301042480734 is a deficient number, since it is larger than the sum of its proper divisors (650526148826).

1301042480734 is an equidigital number, since it uses as much as digits as its factorization.

1301042480734 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1636154.

The product of its (nonzero) digits is 64512, while the sum is 37.

Adding to 1301042480734 its reverse (4370842401031), we get a palindrome (5671884881765).

The spelling of 1301042480734 in words is "one trillion, three hundred one billion, forty-two million, four hundred eighty thousand, seven hundred thirty-four".

Divisors: 1 2 681229 954923 1362458 1909846 650521240367 1301042480734