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130105908953 is a prime number
BaseRepresentation
bin111100100101011101…
…0101001111011011001
3110102211022012222101122
41321022322221323121
54112424103041303
6135434141055025
712254100656546
oct1711272517331
9412738188348
10130105908953
11501a5437099
1221270257475
13c365b06a57
146423597bcd
1535b72d3e38
hex1e4aea9ed9

130105908953 has 2 divisors, whose sum is σ = 130105908954. Its totient is φ = 130105908952.

The previous prime is 130105908931. The next prime is 130105908967. The reversal of 130105908953 is 359809501031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112227010009 + 17878898944 = 335003^2 + 133712^2 .

It is an emirp because it is prime and its reverse (359809501031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130105908953 is a prime.

It is not a weakly prime, because it can be changed into another prime (130105908253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65052954476 + 65052954477.

It is an arithmetic number, because the mean of its divisors is an integer number (65052954477).

Almost surely, 2130105908953 is an apocalyptic number.

It is an amenable number.

130105908953 is a deficient number, since it is larger than the sum of its proper divisors (1).

130105908953 is an equidigital number, since it uses as much as digits as its factorization.

130105908953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 44.

The spelling of 130105908953 in words is "one hundred thirty billion, one hundred five million, nine hundred eight thousand, nine hundred fifty-three".