1301100101101 has 4 divisors (see below), whose sum is σ = 1302783284412. Its totient is φ = 1299416917792.

The previous prime is 1301100101069. The next prime is 1301100101113. The reversal of 1301100101101 is 1011010011031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 648187620201 + 652912480900 = 805101^2 + 808030^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301100101101 - 2⁵ = 1301100101069 is a prime.

It is a super-2 number, since 2×1301100101101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301100501101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 841590496 + ... + 841592041.

It is an arithmetic number, because the mean of its divisors is an integer number (325695821103).

Almost surely, 2^{1301100101101} is an apocalyptic number.

It is an amenable number.

1301100101101 is a deficient number, since it is larger than the sum of its proper divisors (1683183311).

1301100101101 is an equidigital number, since it uses as much as digits as its factorization.

1301100101101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1683183310.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 1301100101101 its reverse (1011010011031), we get a palindrome (2312110112132).

The spelling of 1301100101101 in words is "one trillion, three hundred one billion, one hundred million, one hundred one thousand, one hundred one".