Base | Representation |
---|---|
bin | 111100100101100101… |
… | …0101110110100111011 |
3 | 110102211121011002102102 |
4 | 1321023022232310323 |
5 | 4112431142421243 |
6 | 135434411254015 |
7 | 12254151541415 |
oct | 1711312566473 |
9 | 412747132372 |
10 | 130110123323 |
11 | 501a7855444 |
12 | 2127174a30b |
13 | c36695106b |
14 | 6423d739b5 |
15 | 35b78679b8 |
hex | 1e4b2aed3b |
130110123323 has 2 divisors, whose sum is σ = 130110123324. Its totient is φ = 130110123322.
The previous prime is 130110123197. The next prime is 130110123329. The reversal of 130110123323 is 323321011031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130110123323 - 230 = 129036381499 is a prime.
It is a super-2 number, since 2×1301101233232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130110123295 and 130110123304.
It is not a weakly prime, because it can be changed into another prime (130110123329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055061661 + 65055061662.
It is an arithmetic number, because the mean of its divisors is an integer number (65055061662).
Almost surely, 2130110123323 is an apocalyptic number.
130110123323 is a deficient number, since it is larger than the sum of its proper divisors (1).
130110123323 is an equidigital number, since it uses as much as digits as its factorization.
130110123323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 130110123323 its reverse (323321011031), we get a palindrome (453431134354).
The spelling of 130110123323 in words is "one hundred thirty billion, one hundred ten million, one hundred twenty-three thousand, three hundred twenty-three".
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