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130110201003331 is a prime number
BaseRepresentation
bin11101100101010110100100…
…010011111111110101000011
3122001200102011121122021212201
4131211112210103333311003
5114023211142424101311
61140415445015534031
736256103033605453
oct3545264423776503
9561612147567781
10130110201003331
113850347655609a
121271428b08a317
13577a4545cac73
14241b51dd45d63
1510096e91479c1
hex7655a44ffd43

130110201003331 has 2 divisors, whose sum is σ = 130110201003332. Its totient is φ = 130110201003330.

The previous prime is 130110201003217. The next prime is 130110201003361. The reversal of 130110201003331 is 133300102011031.

It is a strong prime.

It is an emirp because it is prime and its reverse (133300102011031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130110201003331 - 27 = 130110201003203 is a prime.

It is a super-2 number, since 2×1301102010033312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130110201003299 and 130110201003308.

It is not a weakly prime, because it can be changed into another prime (130110201003361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055100501665 + 65055100501666.

It is an arithmetic number, because the mean of its divisors is an integer number (65055100501666).

Almost surely, 2130110201003331 is an apocalyptic number.

130110201003331 is a deficient number, since it is larger than the sum of its proper divisors (1).

130110201003331 is an equidigital number, since it uses as much as digits as its factorization.

130110201003331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 130110201003331 its reverse (133300102011031), we get a palindrome (263410303014362).

The spelling of 130110201003331 in words is "one hundred thirty trillion, one hundred ten billion, two hundred one million, three thousand, three hundred thirty-one".