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13011101212200 = 233527213100933739
BaseRepresentation
bin1011110101010110001000…
…0100001101111000101000
31201001211221000101112112220
42331111202010031320220
53201133213402242300
643401114542034040
72512010134345500
oct275254204157050
951054830345486
1013011101212200
114166a82487833
12156177b578920
13734c3185c230
1432da52520a00
151786ae069da0
hexbd56210de28

13011101212200 has 576 divisors, whose sum is σ = 50580403272000. Its totient is φ = 2742397378560.

The previous prime is 13011101212189. The next prime is 13011101212231. The reversal of 13011101212200 is 221210111031.

It is a super-2 number, since 2×130111012122002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13011101212200.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 385622931 + ... + 385656669.

It is an arithmetic number, because the mean of its divisors is an integer number (87813200125).

Almost surely, 213011101212200 is an apocalyptic number.

13011101212200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13011101212200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25290201636000).

13011101212200 is an abundant number, since it is smaller than the sum of its proper divisors (37569302059800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011101212200 is a wasteful number, since it uses less digits than its factorization.

13011101212200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34794 (or 34778 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13011101212200 its reverse (221210111031), we get a palindrome (13232311323231).

The spelling of 13011101212200 in words is "thirteen trillion, eleven billion, one hundred one million, two hundred twelve thousand, two hundred".