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130111033303 = 887711465693
BaseRepresentation
bin111100100101100111…
…0001100111111010111
3110102211122212022200101
41321023032030333113
54112431411031203
6135434442554531
712254162351416
oct1711316147727
9412748768611
10130111033303
11501a8317099
1221271b08a47
13c366bac304
14642412d47d
1535b799741d
hex1e4b38cfd7

130111033303 has 4 divisors (see below), whose sum is σ = 130112587768. Its totient is φ = 130109478840.

The previous prime is 130111033267. The next prime is 130111033357. The reversal of 130111033303 is 303330111031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130111033303 - 225 = 130077478871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130111093303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 644076 + ... + 821617.

It is an arithmetic number, because the mean of its divisors is an integer number (32528146942).

Almost surely, 2130111033303 is an apocalyptic number.

130111033303 is a deficient number, since it is larger than the sum of its proper divisors (1554465).

130111033303 is an equidigital number, since it uses as much as digits as its factorization.

130111033303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1554464.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 130111033303 its reverse (303330111031), we get a palindrome (433441144334).

The spelling of 130111033303 in words is "one hundred thirty billion, one hundred eleven million, thirty-three thousand, three hundred three".

Divisors: 1 88771 1465693 130111033303