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130111102321200 = 243452721113573109
BaseRepresentation
bin11101100101010111011010…
…000010010000001000110000
3122001200111111102121222120000
4131211113122002100020300
5114023220014143234300
61140420114254150000
736256134256643400
oct3545273202201060
9561614442558500
10130111102321200
11385038992a85a0
12127144a0ab2300
13577a569266450
14241b5a7926800
15100974d334c00
hex7655da090230

130111102321200 has 1800 divisors, whose sum is σ = 638161914242160. Its totient is φ = 24956331724800.

The previous prime is 130111102321183. The next prime is 130111102321237. The reversal of 130111102321200 is 2123201111031.

130111102321200 is a `hidden beast` number, since 1 + 30 + 1 + 1 + 110 + 2 + 321 + 200 = 666.

It is a tau number, because it is divible by the number of its divisors (1800).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 359 ways as a sum of consecutive naturals, for example, 226740246 + ... + 227313354.

Almost surely, 2130111102321200 is an apocalyptic number.

130111102321200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130111102321200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (319080957121080).

130111102321200 is an abundant number, since it is smaller than the sum of its proper divisors (508050811920960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130111102321200 is a wasteful number, since it uses less digits than its factorization.

130111102321200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 573177 (or 573150 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 130111102321200 its reverse (2123201111031), we get a palindrome (132234303432231).

The spelling of 130111102321200 in words is "one hundred thirty trillion, one hundred eleven billion, one hundred two million, three hundred twenty-one thousand, two hundred".