Base | Representation |
---|---|
bin | 1011110101010110001101… |
… | …0111010111100111110001 |
3 | 1201001211222112101222120001 |
4 | 2331111203113113213301 |
5 | 3201133234442310113 |
6 | 43401121041150001 |
7 | 2512010520543151 |
oct | 275254327274761 |
9 | 51054875358501 |
10 | 13011123010033 |
11 | 4166a93815875 |
12 | 156178692b301 |
13 | 734c36221a65 |
14 | 32da55396761 |
15 | 1786b0e237dd |
hex | bd5635d79f1 |
13011123010033 has 2 divisors, whose sum is σ = 13011123010034. Its totient is φ = 13011123010032.
The previous prime is 13011123010027. The next prime is 13011123010069. The reversal of 13011123010033 is 33001032111031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11616699755584 + 1394423254449 = 3408328^2 + 1180857^2 .
It is a cyclic number.
It is not a de Polignac number, because 13011123010033 - 241 = 10812099754481 is a prime.
It is a super-2 number, since 2×130111230100332 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13011123040033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505561505016 + 6505561505017.
It is an arithmetic number, because the mean of its divisors is an integer number (6505561505017).
Almost surely, 213011123010033 is an apocalyptic number.
It is an amenable number.
13011123010033 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011123010033 is an equidigital number, since it uses as much as digits as its factorization.
13011123010033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13011123010033 its reverse (33001032111031), we get a palindrome (46012155121064).
The spelling of 13011123010033 in words is "thirteen trillion, eleven billion, one hundred twenty-three million, ten thousand, thirty-three".
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