Base | Representation |
---|---|
bin | 10010111011110000100… |
… | …001110011100000010011 |
3 | 11121101101222101120210122 |
4 | 102323300201303200103 |
5 | 132304141033020242 |
6 | 2433420233020455 |
7 | 163000566262361 |
oct | 22736041634023 |
9 | 4541358346718 |
10 | 1301115516947 |
11 | 461888875624 |
12 | 1901b8b5472b |
13 | 9590524bb3c |
14 | 46d8d7a6631 |
15 | 23ca1d23ad2 |
hex | 12ef0873813 |
1301115516947 has 2 divisors, whose sum is σ = 1301115516948. Its totient is φ = 1301115516946.
The previous prime is 1301115516859. The next prime is 1301115516973. The reversal of 1301115516947 is 7496155111031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1301115516947 - 28 = 1301115516691 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1301115516898 and 1301115516907.
It is not a weakly prime, because it can be changed into another prime (1301115516847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650557758473 + 650557758474.
It is an arithmetic number, because the mean of its divisors is an integer number (650557758474).
Almost surely, 21301115516947 is an apocalyptic number.
1301115516947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301115516947 is an equidigital number, since it uses as much as digits as its factorization.
1301115516947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 44.
The spelling of 1301115516947 in words is "one trillion, three hundred one billion, one hundred fifteen million, five hundred sixteen thousand, nine hundred forty-seven".
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