Base | Representation |
---|---|
bin | 1011110101010110100000… |
… | …0001011000011011000011 |
3 | 1201001212011222102000001122 |
4 | 2331111220001120123003 |
5 | 3201133414442212402 |
6 | 43401132511422455 |
7 | 2512012456555514 |
oct | 275255001303303 |
9 | 51055158360048 |
10 | 13011201132227 |
11 | 4167023924171 |
12 | 15617a8b24a2b |
13 | 734c494754cc |
14 | 32da618d0a0b |
15 | 1786b7c05ca2 |
hex | bd5680586c3 |
13011201132227 has 2 divisors, whose sum is σ = 13011201132228. Its totient is φ = 13011201132226.
The previous prime is 13011201132169. The next prime is 13011201132233. The reversal of 13011201132227 is 72223110211031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13011201132227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13011201132196 and 13011201132205.
It is not a weakly prime, because it can be changed into another prime (13011201135227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505600566113 + 6505600566114.
It is an arithmetic number, because the mean of its divisors is an integer number (6505600566114).
Almost surely, 213011201132227 is an apocalyptic number.
13011201132227 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011201132227 is an equidigital number, since it uses as much as digits as its factorization.
13011201132227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 13011201132227 its reverse (72223110211031), we get a palindrome (85234311343258).
The spelling of 13011201132227 in words is "thirteen trillion, eleven billion, two hundred one million, one hundred thirty-two thousand, two hundred twenty-seven".
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