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13011221383619 is a prime number
BaseRepresentation
bin1011110101010110100100…
…1110101000100111000011
31201001212020101111212202012
42331111221032220213003
53201133440133233434
643401134513443135
72512013123652464
oct275255116504703
951055211455665
1013011221383619
1141670342a6358
1215617b38704ab
13734c50716194
1432da64482d6b
151786b98a63ce
hexbd5693a89c3

13011221383619 has 2 divisors, whose sum is σ = 13011221383620. Its totient is φ = 13011221383618.

The previous prime is 13011221383553. The next prime is 13011221383649. The reversal of 13011221383619 is 91638312211031.

It is a strong prime.

It is an emirp because it is prime and its reverse (91638312211031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13011221383619 is a prime.

It is a super-2 number, since 2×130112213836192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13011221383649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505610691809 + 6505610691810.

It is an arithmetic number, because the mean of its divisors is an integer number (6505610691810).

Almost surely, 213011221383619 is an apocalyptic number.

13011221383619 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011221383619 is an equidigital number, since it uses as much as digits as its factorization.

13011221383619 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 41.

The spelling of 13011221383619 in words is "thirteen trillion, eleven billion, two hundred twenty-one million, three hundred eighty-three thousand, six hundred nineteen".