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130112311130 = 2513011231113
BaseRepresentation
bin111100100101101001…
…1000100111101011010
3110102211202021020112022
41321023103010331122
54112432222424010
6135434530214442
712254206253024
oct1711323047532
9412752236468
10130112311130
11501a900a14a
1221272424422
13c367238b19
146424383014
1535b7b4ad55
hex1e4b4c4f5a

130112311130 has 8 divisors (see below), whose sum is σ = 234202160052. Its totient is φ = 52044924448.

The previous prime is 130112311117. The next prime is 130112311157. The reversal of 130112311130 is 31113211031.

It can be written as a sum of positive squares in 2 ways, for example, as 129700099321 + 412211809 = 360139^2 + 20303^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 130112311099 and 130112311108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6505615547 + ... + 6505615566.

Almost surely, 2130112311130 is an apocalyptic number.

130112311130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130112311130 is a deficient number, since it is larger than the sum of its proper divisors (104089848922).

130112311130 is a wasteful number, since it uses less digits than its factorization.

130112311130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13011231120.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 130112311130 its reverse (31113211031), we get a palindrome (161225522161).

The spelling of 130112311130 in words is "one hundred thirty billion, one hundred twelve million, three hundred eleven thousand, one hundred thirty".

Divisors: 1 2 5 10 13011231113 26022462226 65056155565 130112311130