Base | Representation |
---|---|
bin | 111100100101101010… |
… | …1101101001001011111 |
3 | 110102211210120020112011 |
4 | 1321023111231021133 |
5 | 4112432412000111 |
6 | 135434553052051 |
7 | 12254215152340 |
oct | 1711325551137 |
9 | 412753506464 |
10 | 130113000031 |
11 | 501a943a793 |
12 | 212726b7027 |
13 | c36741a561 |
14 | 64244c20c7 |
15 | 35b7c35021 |
hex | 1e4b56d25f |
130113000031 has 8 divisors (see below), whose sum is σ = 149126650400. Its totient is φ = 111205869408.
The previous prime is 130113000023. The next prime is 130113000071. The reversal of 130113000031 is 130000311031.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130113000031 - 23 = 130113000023 is a prime.
It is a super-2 number, since 2×1301130000312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130112999975 and 130113000020.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130113000071) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26627316 + ... + 26632201.
It is an arithmetic number, because the mean of its divisors is an integer number (18640831300).
Almost surely, 2130113000031 is an apocalyptic number.
130113000031 is a deficient number, since it is larger than the sum of its proper divisors (19013650369).
130113000031 is an equidigital number, since it uses as much as digits as its factorization.
130113000031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53259873.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 130113000031 its reverse (130000311031), we get a palindrome (260113311062).
The spelling of 130113000031 in words is "one hundred thirty billion, one hundred thirteen million, thirty-one", and thus it is an aban number.
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