Base | Representation |
---|---|
bin | 1011110101010110111000… |
… | …0011101101010100100110 |
3 | 1201001212110000222012202102 |
4 | 2331111232003231110212 |
5 | 3201134121403433124 |
6 | 43401150530212102 |
7 | 2512015126432565 |
oct | 275255603552446 |
9 | 51055400865672 |
10 | 13011302405414 |
11 | 4167076005215 |
12 | 1561816a24032 |
13 | 734c64443681 |
14 | 32da71133bdc |
15 | 1786c1a5caae |
hex | bd56e0ed526 |
13011302405414 has 16 divisors (see below), whose sum is σ = 19543129115328. Its totient is φ = 6496927444992.
The previous prime is 13011302405411. The next prime is 13011302405417. The reversal of 13011302405414 is 41450420311031.
It is an interprime number because it is at equal distance from previous prime (13011302405411) and next prime (13011302405417).
It is a super-2 number, since 2×130113024054142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13011302405411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18425987 + ... + 19119089.
It is an arithmetic number, because the mean of its divisors is an integer number (1221445569708).
Almost surely, 213011302405414 is an apocalyptic number.
13011302405414 is a deficient number, since it is larger than the sum of its proper divisors (6531826709914).
13011302405414 is a wasteful number, since it uses less digits than its factorization.
13011302405414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 705679.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 13011302405414 its reverse (41450420311031), we get a palindrome (54461722716445).
The spelling of 13011302405414 in words is "thirteen trillion, eleven billion, three hundred two million, four hundred five thousand, four hundred fourteen".
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