13011312030000 has 200 divisors, whose sum is σ = 42011731392576. Its totient is φ = 3468900000000.

The previous prime is 13011312029981. The next prime is 13011312030019. The reversal of 13011312030000 is 3021311031.

13011312030000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13011312029981) and next prime (13011312030019).

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 139483375 + ... + 139576625.

Almost surely, 2^{13011312030000} is an apocalyptic number.

13011312030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13011312030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21005865696288).

13011312030000 is an abundant number, since it is smaller than the sum of its proper divisors (29000419362576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011312030000 is an equidigital number, since it uses as much as digits as its factorization.

13011312030000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97933 (or 97912 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13011312030000 its reverse (3021311031), we get a palindrome (13014333341031).

The spelling of 13011312030000 in words is "thirteen trillion, eleven billion, three hundred twelve million, thirty thousand".