Base | Representation |
---|---|
bin | 111100100101101011… |
… | …0100101010100100111 |
3 | 110102211210222221010221 |
4 | 1321023112211110213 |
5 | 4112432441330434 |
6 | 135435002025211 |
7 | 12254220131215 |
oct | 1711326452447 |
9 | 412753887127 |
10 | 130113230119 |
11 | 501a9587644 |
12 | 212727a8207 |
13 | c36749b1c2 |
14 | 6424541cb5 |
15 | 35b7c7d2b4 |
hex | 1e4b5a5527 |
130113230119 has 8 divisors (see below), whose sum is σ = 133657244960. Its totient is φ = 126570659616.
The previous prime is 130113230111. The next prime is 130113230141. The reversal of 130113230119 is 911032311031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130113230119 - 23 = 130113230111 is a prime.
It is a super-2 number, since 2×1301132301192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130113230093 and 130113230102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130113230111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 177204 + ... + 540025.
It is an arithmetic number, because the mean of its divisors is an integer number (16707155620).
Almost surely, 2130113230119 is an apocalyptic number.
130113230119 is a deficient number, since it is larger than the sum of its proper divisors (3544014841).
130113230119 is an equidigital number, since it uses as much as digits as its factorization.
130113230119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 722169.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 130113230119 in words is "one hundred thirty billion, one hundred thirteen million, two hundred thirty thousand, one hundred nineteen".
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