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13011343302 = 232168557217
BaseRepresentation
bin11000001111000100…
…10101011111000110
31020120210010201112210
430013202111133012
5203121400441202
65551034124250
7640301410326
oct140742253706
936523121483
1013011343302
115577622891
122631580686
1312c4843b09
148b607d286
15512442c6c
hex3078957c6

13011343302 has 8 divisors (see below), whose sum is σ = 26022686616. Its totient is φ = 4337114432.

The previous prime is 13011343291. The next prime is 13011343307. The reversal of 13011343302 is 20334311031.

13011343302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

13011343302 is an admirable number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011343307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1084278603 + ... + 1084278614.

It is an arithmetic number, because the mean of its divisors is an integer number (3252835827).

Almost surely, 213011343302 is an apocalyptic number.

13011343302 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011343302 is a wasteful number, since it uses less digits than its factorization.

13011343302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2168557222.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13011343302 its reverse (20334311031), we get a palindrome (33345654333).

The spelling of 13011343302 in words is "thirteen billion, eleven million, three hundred forty-three thousand, three hundred two".

Divisors: 1 2 3 6 2168557217 4337114434 6505671651 13011343302