Search a number
-
+
13011401203201 is a prime number
BaseRepresentation
bin1011110101010111001111…
…1100100101111000000001
31201001212200220212122211201
42331111303330211320001
53201134322202000301
643401204415541201
72512020436260022
oct275256374457001
951055626778751
1013011401203201
114167116855485
121561843b2a801
13734c7ba55bbb
1432da802d0c49
151786ca576201
hexbd573f25e01

13011401203201 has 2 divisors, whose sum is σ = 13011401203202. Its totient is φ = 13011401203200.

The previous prime is 13011401203181. The next prime is 13011401203237. The reversal of 13011401203201 is 10230210411031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11176825766976 + 1834575436225 = 3343176^2 + 1354465^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011401203201 - 25 = 13011401203169 is a prime.

It is a super-2 number, since 2×130114012032012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13011401204201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505700601600 + 6505700601601.

It is an arithmetic number, because the mean of its divisors is an integer number (6505700601601).

Almost surely, 213011401203201 is an apocalyptic number.

It is an amenable number.

13011401203201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011401203201 is an equidigital number, since it uses as much as digits as its factorization.

13011401203201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13011401203201 its reverse (10230210411031), we get a palindrome (23241611614232).

The spelling of 13011401203201 in words is "thirteen trillion, eleven billion, four hundred one million, two hundred three thousand, two hundred one".