13011401453 has 4 divisors (see below), whose sum is σ = 13011669408. Its totient is φ = 13011133500.

The previous prime is 13011401413. The next prime is 13011401483. The reversal of 13011401453 is 35410411031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13011401453 - 2²⁰ = 13010352877 is a prime.

It is a super-2 number, since 2×13011401453² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011401413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38423 + ... + 165828.

It is an arithmetic number, because the mean of its divisors is an integer number (3252917352).

Almost surely, 2^13011401453 is an apocalyptic number.

It is an amenable number.

13011401453 is a deficient number, since it is larger than the sum of its proper divisors (267955).

13011401453 is an equidigital number, since it uses as much as digits as its factorization.

13011401453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267954.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13011401453 its reverse (35410411031), we get a palindrome (48421812484).

The spelling of 13011401453 in words is "thirteen billion, eleven million, four hundred one thousand, four hundred fifty-three".