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130114023233 is a prime number
BaseRepresentation
bin111100100101101100…
…1100110111101000001
3110102211212111020002112
41321023121212331001
54112433142220413
6135435031025105
712254226643415
oct1711331467501
9412755436075
10130114023233
11501a9a79507
1221272b0b195
13c3676b81bc
1464246aad45
1535b7d882a8
hex1e4b666f41

130114023233 has 2 divisors, whose sum is σ = 130114023234. Its totient is φ = 130114023232.

The previous prime is 130114023217. The next prime is 130114023239. The reversal of 130114023233 is 332320411031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99289900609 + 30824122624 = 315103^2 + 175568^2 .

It is a cyclic number.

It is not a de Polignac number, because 130114023233 - 24 = 130114023217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130114023199 and 130114023208.

It is not a weakly prime, because it can be changed into another prime (130114023239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65057011616 + 65057011617.

It is an arithmetic number, because the mean of its divisors is an integer number (65057011617).

Almost surely, 2130114023233 is an apocalyptic number.

It is an amenable number.

130114023233 is a deficient number, since it is larger than the sum of its proper divisors (1).

130114023233 is an equidigital number, since it uses as much as digits as its factorization.

130114023233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130114023233 its reverse (332320411031), we get a palindrome (462434434264).

The spelling of 130114023233 in words is "one hundred thirty billion, one hundred fourteen million, twenty-three thousand, two hundred thirty-three".