Base | Representation |
---|---|
bin | 1011110101010111010010… |
… | …0011100010000001010111 |
3 | 1201001212201122002021100111 |
4 | 2331111310203202001113 |
5 | 3201134332310123111 |
6 | 43401205422423451 |
7 | 2512020622113325 |
oct | 275256443420127 |
9 | 51055648067314 |
10 | 13011411411031 |
11 | 4167121597800 |
12 | 1561847431b87 |
13 | 734c80bbb237 |
14 | 32da817cad15 |
15 | 1786cb3e0a21 |
hex | bd5748e2057 |
13011411411031 has 24 divisors (see below), whose sum is σ = 14367869853120. Its totient is φ = 11773954019520.
The previous prime is 13011411411001. The next prime is 13011411411049.
13011411411031 is nontrivially palindromic in base 10.
13011411411031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13011411411031 - 213 = 13011411402839 is a prime.
It is a super-2 number, since 2×130114114110312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13011411410993 and 13011411411011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13011411411001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 67371601 + ... + 67564453.
It is an arithmetic number, because the mean of its divisors is an integer number (598661243880).
Almost surely, 213011411411031 is an apocalyptic number.
13011411411031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13011411411031 is a deficient number, since it is larger than the sum of its proper divisors (1356458442089).
13011411411031 is a wasteful number, since it uses less digits than its factorization.
13011411411031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195447 (or 195436 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 22.
It can be divided in two parts, 1301141 and 1411031, that added together give a palindrome (2712172).
The spelling of 13011411411031 in words is "thirteen trillion, eleven billion, four hundred eleven million, four hundred eleven thousand, thirty-one".
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