13011444331 has 4 divisors (see below), whose sum is σ = 13037007600. Its totient is φ = 12985881064.

The previous prime is 13011444301. The next prime is 13011444361. The reversal of 13011444331 is 13344411031.

It is a happy number.

13011444331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13011444301) and next prime (13011444361).

It is a cyclic number.

It is not a de Polignac number, because 13011444331 - 2²⁷ = 12877226603 is a prime.

It is a super-2 number, since 2×13011444331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011444296 and 13011444305.

It is not an unprimeable number, because it can be changed into a prime (13011444301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12780871 + ... + 12781888.

It is an arithmetic number, because the mean of its divisors is an integer number (3259251900).

Almost surely, 2^13011444331 is an apocalyptic number.

13011444331 is a deficient number, since it is larger than the sum of its proper divisors (25563269).

13011444331 is an equidigital number, since it uses as much as digits as its factorization.

13011444331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25563268.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13011444331 its reverse (13344411031), we get a palindrome (26355855362).

The spelling of 13011444331 in words is "thirteen billion, eleven million, four hundred forty-four thousand, three hundred thirty-one".