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130114950252817 is a prime number
BaseRepresentation
bin11101100101011010111111…
…011000111100100100010001
3122001200212102121012011101211
4131211122333120330210101
5114023300404231042232
61140421552152500121
736256331522554045
oct3545327730744421
9561625377164354
10130114950252817
1138505493367572
12127151956aa641
13577aa3051366a
14241b8509b4025
1510098c606ca47
hex7656bf63c911

130114950252817 has 2 divisors, whose sum is σ = 130114950252818. Its totient is φ = 130114950252816.

The previous prime is 130114950252809. The next prime is 130114950252851. The reversal of 130114950252817 is 718252059411031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91500110293761 + 38614839959056 = 9565569^2 + 6214084^2 .

It is a cyclic number.

It is not a de Polignac number, because 130114950252817 - 23 = 130114950252809 is a prime.

It is not a weakly prime, because it can be changed into another prime (130114950252857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65057475126408 + 65057475126409.

It is an arithmetic number, because the mean of its divisors is an integer number (65057475126409).

Almost surely, 2130114950252817 is an apocalyptic number.

It is an amenable number.

130114950252817 is a deficient number, since it is larger than the sum of its proper divisors (1).

130114950252817 is an equidigital number, since it uses as much as digits as its factorization.

130114950252817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 604800, while the sum is 49.

The spelling of 130114950252817 in words is "one hundred thirty trillion, one hundred fourteen billion, nine hundred fifty million, two hundred fifty-two thousand, eight hundred seventeen".