Base | Representation |
---|---|
bin | 10010111011110010110… |
… | …010000110100111011001 |
3 | 11121101111121120101201011 |
4 | 102323302302012213121 |
5 | 132304230224001321 |
6 | 2433424103453521 |
7 | 163001535640252 |
oct | 22736262064731 |
9 | 4541447511634 |
10 | 1301153343961 |
11 | 4618a8161619 |
12 | 1902097572a1 |
13 | 959100345a3 |
14 | 46d94811b29 |
15 | 23ca52e6ae1 |
hex | 12ef2c869d9 |
1301153343961 has 2 divisors, whose sum is σ = 1301153343962. Its totient is φ = 1301153343960.
The previous prime is 1301153343943. The next prime is 1301153344009. The reversal of 1301153343961 is 1693433511031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 950001102400 + 351152241561 = 974680^2 + 592581^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301153343961 - 29 = 1301153343449 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301153343361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650576671980 + 650576671981.
It is an arithmetic number, because the mean of its divisors is an integer number (650576671981).
Almost surely, 21301153343961 is an apocalyptic number.
It is an amenable number.
1301153343961 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301153343961 is an equidigital number, since it uses as much as digits as its factorization.
1301153343961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 87480, while the sum is 40.
Adding to 1301153343961 its reverse (1693433511031), we get a palindrome (2994586854992).
The spelling of 1301153343961 in words is "one trillion, three hundred one billion, one hundred fifty-three million, three hundred forty-three thousand, nine hundred sixty-one".
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