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13011830580547 is a prime number
BaseRepresentation
bin1011110101011000110110…
…0010100010010101000011
31201001220210211211021211101
42331112031202202111003
53201141212112034142
643401315154555231
72512034202025021
oct275261542422503
951056724737741
1013011830580547
114167317165a97
121561943898b17
137350199b1c36
1432dac1341711
151787030de0b7
hexbd58d8a2543

13011830580547 has 2 divisors, whose sum is σ = 13011830580548. Its totient is φ = 13011830580546.

The previous prime is 13011830580491. The next prime is 13011830580599. The reversal of 13011830580547 is 74508503811031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13011830580547 - 219 = 13011830056259 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011830580497 and 13011830580506.

It is not a weakly prime, because it can be changed into another prime (13011830580247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505915290273 + 6505915290274.

It is an arithmetic number, because the mean of its divisors is an integer number (6505915290274).

Almost surely, 213011830580547 is an apocalyptic number.

13011830580547 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011830580547 is an equidigital number, since it uses as much as digits as its factorization.

13011830580547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 46.

The spelling of 13011830580547 in words is "thirteen trillion, eleven billion, eight hundred thirty million, five hundred eighty thousand, five hundred forty-seven".