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130120002240097 is a prime number
BaseRepresentation
bin11101100101011111101100…
…100000101111111001100001
3122001201100110200101201002211
4131211133230200233321201
5114023341231033140342
61140424145342242121
736256600646003662
oct3545375440577141
9561640420351084
10130120002240097
1138507646052371
1212716165586341
13577b35707504c
14241bbad929369
151009abe842c17
hex7657ec82fe61

130120002240097 has 2 divisors, whose sum is σ = 130120002240098. Its totient is φ = 130120002240096.

The previous prime is 130120002240083. The next prime is 130120002240157. The reversal of 130120002240097 is 790042200021031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108672368556816 + 21447633683281 = 10424604^2 + 4631159^2 .

It is a cyclic number.

It is not a de Polignac number, because 130120002240097 - 215 = 130120002207329 is a prime.

It is not a weakly prime, because it can be changed into another prime (130120002240017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65060001120048 + 65060001120049.

It is an arithmetic number, because the mean of its divisors is an integer number (65060001120049).

Almost surely, 2130120002240097 is an apocalyptic number.

It is an amenable number.

130120002240097 is a deficient number, since it is larger than the sum of its proper divisors (1).

130120002240097 is an equidigital number, since it uses as much as digits as its factorization.

130120002240097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

The spelling of 130120002240097 in words is "one hundred thirty trillion, one hundred twenty billion, two million, two hundred forty thousand, ninety-seven".