Base | Representation |
---|---|
bin | 11000001111001001… |
… | …10110000110000001 |
3 | 1020120211101010221122 |
4 | 30013210312012001 |
5 | 203122033014103 |
6 | 5551100202025 |
7 | 640310120264 |
oct | 140744660601 |
9 | 36524333848 |
10 | 13012001153 |
11 | 5577a32068 |
12 | 2631839315 |
13 | 12c4a14388 |
14 | 8b61b0cdb |
15 | 512522b38 |
hex | 307936181 |
13012001153 has 2 divisors, whose sum is σ = 13012001154. Its totient is φ = 13012001152.
The previous prime is 13012001131. The next prime is 13012001201. The reversal of 13012001153 is 35110021031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10334145649 + 2677855504 = 101657^2 + 51748^2 .
It is a cyclic number.
It is not a de Polignac number, because 13012001153 - 210 = 13012000129 is a prime.
It is not a weakly prime, because it can be changed into another prime (13012001053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506000576 + 6506000577.
It is an arithmetic number, because the mean of its divisors is an integer number (6506000577).
Almost surely, 213012001153 is an apocalyptic number.
It is an amenable number.
13012001153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13012001153 is an equidigital number, since it uses as much as digits as its factorization.
13012001153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 13012001153 its reverse (35110021031), we get a palindrome (48122022184).
The spelling of 13012001153 in words is "thirteen billion, twelve million, one thousand, one hundred fifty-three".
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