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1301201240142 = 232111027805087
BaseRepresentation
bin10010111011110101101…
…000110100000001001110
311121101121221200202220210
4102323311220310001032
5132304330004141032
62433432534223250
7163002660023256
oct22736550640116
94541557622823
101301201240142
114619221a5741
121902217b4b26
1395919c3421b
1446d9ad1c966
1523ca96082cc
hex12ef5a3404e

1301201240142 has 16 divisors (see below), whose sum is σ = 2614736143872. Its totient is φ = 431678136120.

The previous prime is 1301201240137. The next prime is 1301201240153. The reversal of 1301201240142 is 2410421021031.

It is a super-3 number, since 3×13012012401423 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 513901278 + ... + 513903809.

It is an arithmetic number, because the mean of its divisors is an integer number (163421008992).

Almost surely, 21301201240142 is an apocalyptic number.

1301201240142 is an abundant number, since it is smaller than the sum of its proper divisors (1313534903730).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301201240142 is a wasteful number, since it uses less digits than its factorization.

1301201240142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1027805303.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1301201240142 its reverse (2410421021031), we get a palindrome (3711622261173).

The spelling of 1301201240142 in words is "one trillion, three hundred one billion, two hundred one million, two hundred forty thousand, one hundred forty-two".

Divisors: 1 2 3 6 211 422 633 1266 1027805087 2055610174 3083415261 6166830522 216866873357 433733746714 650600620071 1301201240142