13012100111 has 4 divisors (see below), whose sum is σ = 13012328424. Its totient is φ = 13011871800.

The previous prime is 13012100099. The next prime is 13012100113. The reversal of 13012100111 is 11100121031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13012100111 - 2¹⁴ = 13012083727 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13012100092 and 13012100101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13012100113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50456 + ... + 169026.

It is an arithmetic number, because the mean of its divisors is an integer number (3253082106).

Almost surely, 2^13012100111 is an apocalyptic number.

13012100111 is a deficient number, since it is larger than the sum of its proper divisors (228313).

13012100111 is a wasteful number, since it uses less digits than its factorization.

13012100111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228312.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 13012100111 its reverse (11100121031), we get a palindrome (24112221142).

The spelling of 13012100111 in words is "thirteen billion, twelve million, one hundred thousand, one hundred eleven".